Question: python Assuming we have the following list of numbers: >>> list_of_numbers = [48, 24, 37, 25, 38, 16, 50] The heap would be created as

python  python Assuming we have the following list of numbers: >>> list_of_numbers
= [48, 24, 37, 25, 38, 16, 50] The heap would be
created as follows: heap=[] for new_number in list_of_numbers: heap = insert_heap(heap, new_number)
The output would be : >>>heap [50, 38, 48, 24, 25, 16,
Assuming we have the following list of numbers:
>>> list_of_numbers = [48, 24, 37, 25, 38, 16, 50]
The heap would be created as follows:
heap=[]
for new_number in list_of_numbers:
heap = insert_heap(heap, new_number)
The output would be :
>>>heap
[50, 38, 48, 24, 25, 16, 37]
Create a three way heap (Modify the above functions) so that when creating the heap you would get the following:
>>> heap
[50, 48, 37, 25, 24, 16, 38]

LTE II. 1: - -... ! = parent value heap/index),heaplparent_index] = parent_value, my_value else: #finish return heap (heap = heapify(heap.parent_index return heap Assuming we have the following list of numbers flict nf number LTE II. 1:1) - - ! = parent_value heaplindex), heap[parent_index] = parent_value, my_value else: finish return heap (heap = heapify(heap.parent_index return heap Assuming we have the following list of numbers [list of numbers = [48, 24, 37, 25, 38, 16,50 = parent_value: heap[index], heap[parent_index] = LE ln. 1: . - 2020 - = parent_value: heap[index], heap[parent_index] = parent_value, my_value else: #finish return heap heap = heapify(heap,parent_index) return heap

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!