PYTHON CODE PLEASE!!!

This year is an election year, and it looks like it might be a close one, so here are some

election statistics to ponder.

Suppose a million votes are cast for two opposing candidates. Suppose that voters are

slightly less likely to vote for one candidate than for the other. Specifically, assume

that on average $49\mathrm{.}9\%$ of voters will choose the less favored candidate. What are the

chances that there is a tie $($each candidate gets exactly $500,000$ votes$)?$ What are the

chances that the less$-$favored candidate will actually win?

To answer these questions, assume that the votes for the less$-$favored candidate follow

a binomial distribution such that the chance $P_B$ of the candidate getting exactly $k$

votes out of a total of $n$ votes is

$P_B(k$;$n,p)=\frac{n!}{k!(n-k)!}{p}^k(1-p{)}^{(n-k)}$

where $p=0\mathrm{.}499$ is the probability that any individual voter will vote for this candi$-$

date. This equation may be difficult to solve numerically, owing to the large numbers

involved. To mitigate this difficulty, you may want to make use of the approximation

to the binomial distribution given in Exercise $3$ of Lab $5,$ which should be very good

for $p$ near $0\mathrm{.}5$ and $n=1,000,000.$

Write a Python script

elect.py which takes command$-$line input from the user to

specify $p.$ Have your code print out the following:

probability p that voter chooses candidate: XXX

probability of tie: YYY

probability of win: ZZZ

Note: this probabilistic interpretation of voters does not mean that voters themselves

necessarily act in a random fashion. Instead, probabilities are assigned because the

many influences on individual choices prevent us from knowing much more than how

voters behave on average, as gleaned from surveys and polls. In this sense the situation

is similar to a coin$-$flipping experiment, wherein unpredictable processes influence the

outcome and we only know $($if the coin is a fair$/"$honest$"$ one$)$ that on average, we'll

get $50\%$ heads. $(p=0\mathrm{.}5$ in the above equation$).$ Play around with different input values

for $p.$ I think it is amazing how finely tuned $p$ must be for there to be a close election!