PYTHON:

Given a string, str_a, return each word and the word frequency in descending order by frequency.

Constraints

Not case sensitive.

A word does not contain any spaces

If a word ends with a punctuation mark, ignore it.

The order doesn't matter for words with the same frequency (therefore your answer may differ).

Examples

"Fa la la, la la la, la la la, la la la, fa la la, la la la, la la la la" -> [('la', 20), ('fa', 2)]

"lala"-> [('lala', 1)]

START with this code:

def strFrequency(str_a):