Python HELP

1) Assume there is a variable, h already associated with a positive integer value. Write the code necessary to count the number of perfect squares whose value is less than h, starting with 1. (A perfect square is an integer like 9, 16, 25, 36 that is equal to the square of another integer (in this case 3*3, 4*4, 5*5, 6*6 respectively).) Assign the sum you compute to a variable q. For example, if h is 19, you would assign 4 to q because the perfect squares (starting with 1) that are less than h are: 1, 4, 9, 16.

2)

A geometric progression is a sequence of numbers in which each value (after the first) is obtained by multiplying the previous value in the sequence by a fixed value called the common ratio. For example the sequence 3, 12, 48, 192, ... is a geometric progression in which the common ratio is 4.

Given the positive integer ratio greater than 1, and the non-negative integer n, create a list consisting of the geometric progression of numbers between (and including) 1 and n with a common ratio of ratio. For example, if ratio is 2 and n is 8, the list would be [1, 2, 4, 8].

Associate the list with the variable geom_prog

need help with code