Python Pls

Only One Return statement requires

ex_dict = { 'Ceaser': [('Iron', 30, 40), ('Deli' , 20, 50), ('Iron',-10, 60), ('Apron', 20, 55)], 'Baily': [('Iron', 20, 40), ('Iron',-10, 45), ('Ice', 40, 30), ('Iron',-10, 35)], 'Aaron': [('Iron', 20, 10), ('Dell', 10, 50), ('Apron', 80, 80), ('Deli', -10, 55)], 'Death': [('Apron', 40, 80), ('Apron', 40, 85), ('Apron',-40, 90)] }

def One_return_name:

#Only one return statement (that means you cannot use any other statement.)

#Aaron = 20+10+80+10 = 120

#Death = 40+40+40 = 120

#Baily = 20+10+40+10 = 80

#Ceaser = 30+20+10+20 = 80

#If the result is same, sort by alphabetical order.

Output = ['Aaron', 'Death', 'Baily', 'Ceaser'].

1)Create a function name One_return_name(dicto). This function takes a dictionary and returns the list of the name of people that have largest number of products

For example. only one return line means

def online(db):

return x for x in db.....

so you cannot use any code beside one return statement

2) Create a function one_product_num(dicto). This function take dictionary and returns the list that contains (product name: total_num)

ex_dict = { 'Ceaser': [('Iron', 30, 40), ('Deli' , 20, 50), ('Iron',-10, 60), ('Apron', 20, 55)], 'Baily': [('Iron', 20, 40), ('Iron',-10, 45), ('Ice', 40, 30), ('Iron',-10, 35)], 'Aaron': [('Iron', 20, 10), ('Dell', 10, 50), ('Apron', 80, 80), ('Deli', -10, 55)], 'Death': [('Apron', 40, 80), ('Apron', 40, 85), ('Apron',-40, 90)] }

def one_product_num(dicto)

#Iron = 30+10+20+10+10+20 = 100

#Deli = 20+10+10 = 40

#Ice = 40

#Apron = 20+80+40+40+40 = 220

#If the total number same, sort by alphabetical order

#This one also only can use one return statement

Output = [('Apron ',220), ('Iron',100), ('Deli ',40), ('Ice ',40)]