Python:

Q1: Make Adder Increasing Write a function which takes in an integer n and returns a one-argument function. This function should take in some value x and return n + x the first time it is called, similar to make_adder . The second time it is called, however, it should return n x 1, then n x 2 the third time, and so on def make_adder_inc(n): er_inc(5) >>>adderl make add >>> adder2 = make-adder-inc (6) >>> adder1 (2) >>> adder!(2) # 5 + 2 + 1 >>> adder!(10) #5+10+2 17 >>adderl (x) for x in [1, 2, 3]1 [9, 11, 13] >>> adder2 (5) YOUR CODE HERE **