Python: Would someone explain the following errors. I am having to use Python for the first time and I installed it using on visual studio. thank you.

or line in urllib2.urlopen("http://www.cisco.com"): #here we are opening the URL www.cisco.com File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 154, in urlopen return opener.open(url, data, timeout) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 435, in open response = meth(req, response) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 548, in http_response 'http', request, response, code, msg, hdrs) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 467, in error result = self._call_chain(*args) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 407, in _call_chain result = func(*args) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 654, in http_error_302 return self.parent.open(new, timeout=req.timeout) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 429, in open response = self._open(req, data) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 447, in _open '_open', req) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 407, in _call_chain result = func(*args) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 1241, in https_open context=self._context) File "C:\Users\Admin\Anaconda2\lib\urllib2.py", line 1198, in do_open raise URLError(err) urllib2.URLError: PS C:\Users\Admin>