Python3.4 Find the brand problem. Please help with this problem.

class Car: def __init__(self, vin, brand, model, year): self._vin = vin self._brand = brand self._model = model self._year = year self._repairs = [] def add_repair(self, repair_desc, repair_cost): self._repairs += [Repair(repair_desc, repair_cost)] def __repr__(self): return 'VIN: ' + self._vin + ' ' + \ ' Brand: ' + self._brand + ' ' + \ ' Model: ' + self._model + ' ' + \ ' Year: ' + str(self._year) + ' '  class Repair: def __init__(self, desc, cost): self._desc = desc self._cost = cost def __repr__(self): return self._desc + ': $' + str(self._cost) 

There is provided database.

if __name__ == '__main__': def reset_car_database(): c01 = Car('XYZ123X', 'Toyota', 'Camry', 2012) c02 = Car('HSY113Y', 'Honda', 'Civic', 2016) c03 = Car('MZJ291E', 'Ford', 'Escape', 2009) c04 = Car('KJD922P', 'Jeep', 'Wrangler', 2011) c05 = Car('TRQ235K', 'Hyundai', 'Sonata', 2017) c06 = Car('JNH47GB', 'Toyota', 'Camry', 2011) c07 = Car('K83JDE3', 'Honda', 'Pilot', 2009) c08 = Car('MCJD83J', 'Hyundai', 'Elantra', 2013) c09 = Car('9EM2JSK', 'Toyota', 'Camry', 2002) c10 = Car('JF83JKS', 'Honda', 'Civic', 2012) c01.add_repair('Broken axle', 2900) c01.add_repair('Punctured tire', 40) c02.add_repair('Cracked windshield', 1000) c04.add_repair('Oil change', 45) c04.add_repair('New clearcoat', 550) c05.add_repair('Punctured tire', 30) c05.add_repair('Cracked windshield', 1000) c06.add_repair('Popped dents', 75) c06.add_repair('Broken headlight', 80) c06.add_repair('Broken taillight', 95) c07.add_repair('Rebuilt engine', 4880) c09.add_repair('Broken headlight', 80) c09.add_repair('Punctured tire', 80) c10.add_repair('Replaced windshield wipers', 125) car_list1 = [c02, c03, c05, c06, c07, c08, c09] car_list2 = [c01, c03, c04, c05, c06, c08, c09, c10] car_list3 = [c03, c04, c08] return car_list1, car_list2, car_list3 

Part III: Which Brand Has the Worst Repair Record? (3 points) Write a function find worst brand that searches a list of cars and returns the brand of car that has the worst repair record in terms of total repair costs. Since there might be several cars of the same brand, it will be necessary to sum the repair costs for all cars of each brand, determine which brand had the greatest total repair cost over all cars in the list, and finally, return the name of that brand. If two (or more) brands have the same maximum total repair code, the function can return either brand. Hint: consider using a dictionary, where the keys are brands and the values are the total costs for the brands. Another hint: to retrieve a list of the keys in a dictionary, you can use this syntax: my dict code that stores key/value pairs in my dict. key list. my dict keys The idea then is to iterate over the list of keys, find the maximum value, and return the key for that maximum value. In the context of the find-worst-brand function, finding the key with the largest value is equivalent to finding the brand with the highest total cost. Examples: Function Call Return Value find worst-brand (cars1) "Honda" find worst-brand (cars2) "Toyota" find worst-brand (cars3) "Jeep" Note that the quotation marks displayed in the examples are there to emphasize that the return values are strings. You should not add quotation marks to your return values