Q$10$: Putting it all together $(1$ point$)$

Here, we'll update the values in dictionary, storing the output in a dictionary called other$\_$dictionary. This new dictionary will have the same keys, but some values will be updated.

The values in other$\_$dictionary should be updated, such that if the value in the original dictionary is$...$

odd: update the the value stored in the dictionary to store the squared difference of the original value and $\text{'}10\text{'}.$ Remember, you created a function to do this above.$)$

even: store the original value $($from dictionary$).$

Hints:

to loop through key$-$value pairs in a dictionary, check out the $.$items method

You created a squared$\_$diff function above.