Q$.1.,(\frac{\text{d}\text{e}\text{l}\text{T}}{\text{d}\text{e}\text{l}}{)}_{3,3}=4\mathrm{.}0\frac{C}{c}m$

$x=y=4cm$

$=55$

Derive the expression of the temperature at node $1(T_1)$ in terms of $T_5$ and $T_6$ next to an

irregular boundary with derivative boundary conditions for the angle shown in the table

below. A line is drawn connecting the boundary and inner nodes. Consider $x=y,,$ and

$(\frac{\text{d}\text{e}\text{l}\text{T}}{\text{d}\text{e}\text{l}}{)}_3$ the values of which can be taken from the table below. The diagram is shown below.

Each student should refer to the table below to see his student ID for the corresponding

problem set he needs to attempt.

$($Note: Keep the calculator mode in degrees. Show all the steps in detail. Use and show

appropriate units throughout the solution$)$