$Q1{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(x^2+5)(x^3-1)dx$

$Q2{\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^3-3x^2+5x-7}{x^2}dx$

$Q3{\displaystyle \underset{-1}{\overset{1}{}}}{x}^3-x^{2}dx$

$Q4y=\frac{x^3+1}{x},x-$axis, $x=1,$ and $x=2.$ Approximate your answer $to2$

decimal places.