Question: Q = 200k = 400L = 8R = 0.18 5. The temperature 6' of a pipe with inner radius r is given by _ Q

Q = 200k = 400L = 8R = 0.18

5. The temperature 6' of a pipe with inner radius r is given by _ Q 27rkL where Q is the heat transfer rate, L is the length of the pipe, and k is the thermal conductivity. 6(r) = ln(r), (if? (a) Find the rate of change of temperature as a function of radius. ' dr (b) Find the value of the rate of change of temperature for T = R

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