Q$34.$ Give the Java SE program below:

import java.util.$*$;

class Name$\{$

private String first $,$ last;

Name$($String f$,$ String l$)\{$first f; last$=$l;$\}$

Name$()\{\}$

@Override public String toString$()\{$ return first $++$last;$\}$

Public static int compareByLastName$($Name n$1,$ Name n$2)$

$\{$

return n$1.$last.compareTo$($n$2.$last$)$;

$\}$

$\}$

public class MethodRefTest$\{$

public static void main$($String$[]$ args$)\{$

Name n$1=$ new Name$($Harry$,$Homeowner$)$;

Name n$2=$new Name$($Paul$,$Painter$)$;

Name n$3=$new Name$($Jane$,$Doe$)$;

List nameList$=$Arrays.asList$($n$1,$n$2,$n$3)$;

$******$

Which of the following lines of code correctly sunstitute $******$ to cause the program to compile and generate the output?

Jane Joe

Harry Homeowner

Paul Painter

a$.$ nameList.sort$($n$1$::compareByLastName$)$;

nameList.forEach$($System$.$out::println$)$;

b$.$ nameList.sort$($Name::compareByLastName$)$;

nameList.forEach$($System$.$out::println$)$;

c$.$ nameList.sort$($Name::compareByLastName$)$;

nameList.forEach$($System$.$out::println$())$;

d$.$ nameList.sort$($Name::compareByLastName$)$;

nameList.forEach$($System$.$out.println$)$;

e$.$ nameList.sort$($Name::compareByLastName$)$;

nameList.forEach$($System$.$out.println$())$;