Q$5$

Solve the following LP problem graphically to answer question $2$~$5.$

Max: $3$X$1+4$X$2$

S$.$T$.$

X$1<=12$

X$2<=10$

$4$X$1+6$X$2<=72$

Non$-$negativity

$2.$ What is the optimal solution?

$($a$)(0,10)$

$($b$)(12,0)$

$($c$)(12,4)$

$($d$)(5,15)$

$3.$ What is the optimal objective value?

$($a$)60$

$($b$)52$

$($c$)36$

$($d$)0$