$Q6$: Determine whether the improper integral diverges $or$ converges. Evaluate the integral

$ifit$ converges:

$a{\displaystyle \underset{0}{\overset{4}{}}}\frac{1}{\sqrt[\phantom{2}]{x}}dx$

$b{\displaystyle \underset{0}{\overset{2}{}}}\frac{1}{(x-1{)}^2}dx$

$c{\displaystyle \underset{-}{\overset{0}{}}}{e}^{5x}dx.$