Question: Q 7 . ( a ) A primary clarifier with a surface area overflow rate of 5 5 m 3 m 2 . day receives

Q7.
(a) A primary clarifier with a surface area overflow rate of 55m3m2. day receives
a wastewater from an equivalent population of 45,000 having a capita flow
rate of 550Ld and a per capita suspended solids (SS) of 32gd.
(i) Determine the clarifier diameter and depth based on a 2-hour hydraulic
retention time.
(ii) Determine the volume of primary sludge produced daily if 75% of the SS
are removed by the clarification process. Assume that the sludge contains
1.5% SS, the sludge specific gravity is 1.005, and a water density of 1,000
kgm3.
(4 marks)
(b) An activated sludge process is used to treat a combined wastewater from two
separate sources of seafood processing and raw sugar refining, respectively.
The seafood processing produces a wastewater stream of 200m3d with 550
BOD5L, and the sugar refinery produces another wastewater stream of 320
m3d with 650BOD5L. The activated sludge reactor is operating at an organic
loading rate of 4kgBOD5m3*d.
(i) Calculate the volume of the reactor and the hydraulic retention time
based on the combined wastewater flow and BOD5 concentration.
(6 marks)
(ii) For a Food/Microorganism ratio of 0.6kgBOD5kg MLVSS.d, what MLVSS
concentration should be maintained in the aeration tank?
(3 marks)
(iii) Estimate the mean cell residence time, assuming an effluent volatile solids
concentration of 20mgL and the daily amount of waste sludge is 95m3
that contains 1% of volatile solids.
(3 marks)

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