Question: Q [csc x] = - csc x cot x CSC X = 3. Show that dx by using the relationship of sin x

Q [csc x] = - csc x cot x CSC X
= 3. Show that dx by using the relationship of sin x

Q [csc x] = - csc x cot x CSC X = 3. Show that dx by using the relationship of sin x

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