Q1

\fEvaluate the integral. 5 xdx |xdx = (Type an integer or a simplified fraction.)Evaluate the integral. 5 2x 2 dx 4 2x 2 dx = 4 (Type an integer or a simplified fraction.)\fEvaluate the integral. 2 dx 8 X 9 - 2 dx : 8 X (Type an integer or a simplified fraction.)Evaluate the integral. 4 J-er dx (Type an integer or decimal rounded to the nearest thousandth as needed.) Evaluate the integral. ( 5 x 2 + 3 ) dx 2 5 (5x2 + 3) dx = (Type an integer or a simplified fraction.) 2Evaluate the integral. 5 (x2 -4x + 1) dx 5 (x2 -4X + 1 ) 9 dx = 5 (Type an exact answer in simplified form.)Evaluate the integral. [ (2X4 -5) 15 dx (2x 4 - 5) 15 dx = (Type an integer or a simplified fraction.)Evaluate the integral. ( 6X 2 - 4 ) dx 4 I ( ex - 2 -4) dx = 1 (Type an exact answer in simplified form.)Calculate the definite integral. (Type an exact answer in simplified form.) Evaluate the integral. ( 7X (x2 -1) 15 dx O . . . [ 7x (x2 -1) 15 dx = (Type an integer or a simplified fraction.) 0Evaluate the integral. 10 l'd x-3x 5 {E 'l Ix_3dxml:| 5 (Type an integer or decimal rounded to three decimal places as needed.) Evaluate the integral. 5 I e 0.125x dx= El - 9 (Type an integer or decimal rounded to three decimal places as needed.) Evaluate the integral. CO xe - x 2 dx - 3 xe- x 2 dx = (Type an integer or decimal rounded to three decimal places as needed.)(A) Find the average value of the function over the indicated interval. (B) Graph the function and its average value over the indicated interval in the same viewing window. f(x) = 400 - 60x;[0,5] . . . (A) The average value isFor the function f(x) = - 5x2 4, do the following. (A) Find the average value of f(x) on the interval [0, 2]. (B) Use a graphing calculator to graph the function and its average value over the interval [0, 2] in the same viewing window. E (A) Find the average value of f(x) on the interval [0, 2]. The average value is E. (Type an integer or a simplied fraction.) (A) Find the average value of the function over the indicated interval. (B) Graph the function and its average value over the indicated interval in the same viewing window. 1'00 = 1511.81]