Question: Q2. [7 points] Consider a 48-bit virtual address space. The system uses a page size of 4KB and two- level hierarchical paging. Therefore, the page

Q2. [7 points] Consider a 48-bit virtual address space. The system

Q2. [7 points] Consider a 48-bit virtual address space. The system uses a page size of 4KB and two- level hierarchical paging. Therefore, the page table is divided into 4KB pages and the logical address has the following format: P1 P2 Offset Below are the relevant tables. The values are provided in hexadecimal. Outer Page Table 0 Page A of PT 1 Page B of PT (rest are invalid) Page A of Page Table 0 FEE 1 3BC 2 124 3 C3D (rest are invalid) Page B of the Page Table 0 330 1 44B 2 E55 (rest are invalid) X X a) [3 points] What is the size (number of bits) of each of the following logical address fields: Size of P1 = Size of P2= bits Size of Offset bits bits = b) [4 points] what is the physical/logical address corresponding to each of the following shown logical physical addresses. Answer Bad logical address if the logical address is invalid. Logical Address Physical Address 000000000000 000003003102 000001002777 4BB3BC

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