Question: Q2. Consider the RSA algorithm with public key e = 5 and m = 91. (Note that this is a mock example of RSA. The

 Q2. Consider the RSA algorithm with public key e = 5

Q2. Consider the RSA algorithm with public key e = 5 and m = 91. (Note that this is a mock example of RSA. The numbers e, d and m consist of hundreds of digits in real life RSA algorithms.) a. [10 pts] What would be a suitable private key, d? b. [5 pts] Suppose you would like to send the plaintext corresponding to number "5" using this RSA mechanism. What is the number corresponding to the "ciphertext"? c. [5 pts] How does the receiver of the message decrypt the ciphertext

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