Question: Q4 In JAVA: implement the code below and explain what you see and why making a a global variable does not affect the output... In

Q4 In JAVA:

implement the code below and explain what you see and why making a

a global variable does not affect the output...Q4 In JAVA: implement the code below and explain what you see

In this case, b is the parameter that changes and controls the recursion The parameters a is not essential to the recursion itself. To see this, let's make a into a global public class PowerExample4 i . /7 Declare "a" as global to be set in main() and accessed elsewhere. static int a; public static void main (String[] argv) a=3; int p - power (2); system . out . printin ( "3"4 = " + p); // Only "b" is passed as parameter. ppower (4) system . out . printin ( "3"4 = " + p); a- 2; ppower (8) System.out.println ("28"p) // Only one parameter static int power (int b) int p; if(b-0) { p=1; else { p = (a * power (b-1)); System.out.println ("Intermediate result: " + a + "*"+ b+ "-"+ p); return p; In-Class Exercise 4: Implement and execute the above program. Explain what you see and why making a a global variable does not affect the output

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