Question: Q4. Which equation can be solved by referencing the graph below? 57114 5n1/2 O tanx = secx O secx = tanx + 1 tanx +

 Q4. Which equation can be solved by referencing the graph below?57114 5n1/2 O tanx = secx O secx = tanx + 1tanx + 1 = csc.x O tanx = cscx= sinx + 2?
Q 2. Which of the following is a solution to the equationcsc x + O 1.625 O 2.984 O 2 O -0.384Q5. Whichequation can be solved by referencing the graph below? -11/2 -71/4 3Ti/4

Q4. Which equation can be solved by referencing the graph below? 57114 5n1/2 O tanx = secx O secx = tanx + 1 tanx + 1 = csc.x O tanx = cscx= sinx + 2? Q 2. Which of the following is a solution to the equation csc x + O 1.625 O 2.984 O 2 O -0.384Q5. Which equation can be solved by referencing the graph below? -11/2 -71/4 3Ti/4 517/4 371/2 7 1/4 911/4 -1 -2 -3 3 cosx - 1 = sinx 3 sinx = cosx + 1 cosx = sinx - 1 sin (3x) = cosx + 1

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