Question: Question 1 ( 1 point ) What is the optimal time complexity to count the number of nodes in a linked list? Question 1 options:

Question 1(1 point)
What is the optimal time complexity to count the number of nodes in a linked list?
Question 1 options:
O(n^2)
O(nlogn)
O(1)
O(n)
Question 2(1 point)
The last node in a singly linked list points to
Question 2 options:
first node
a null pointer
middle node
last node
Question 3(1 point)
What is the space complexity for deleting a linked list
Question 3 options:
O(nlogn)
O(n^2)
O(n)
O(1)
Question 4(1 point)
Minimum number of fields in each node of a doubly linked list is
Question 4 options:
3
1
2
4
Question 5(1 point)
In a doubly linked list, what is the advantage of having both forward and backward pointers?
Question 5 options:
It allows for faster sorting of the list.
It reduces memory usage.
It allows for efficient traversal in both directions.
It ensures that the list contains no duplicates.
Question 6(1 point)
In the best case, the number of comparisons needed to search a singly linked of length n for a given element will be
Question 6 options:
n
1
nlogn
n^2
Question 7(1 point)
If the head pointer of a singly linked list points to nullptr, this indicates
Question 7 options:
The list needs to be destroyed
The list is full and cannot accept new nodes
There are no nodes in the list
There are 10 nodes in the list
Question 8(1 point)
Consider the following operations to insert a new node at the head of a linked list. Does the order of 1 and 2 matter?
1: new->next = head;
2: head = new;
Question 8 options:
TrueFalse
Question 9(1 point)
In the worst case, the number of comparisons needed to search a singly linked of length n for a given element will be
Question 9 options:
1
nlogn
n
n^2
Question 10(1 point)
In a circular linked list, the last node points to the
Question 10 options:
first node
none
middle node
tail node

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