Question 1 16 pts Matrices are extremely useful in solving systems of equations. In solving an equation involving matrices, division in matrices is not possible, so the [ Select ] V needs to be used. To check to see that the correct inverse has been created, the inverse should be [ Select ] v with the original matrix and the result should be the [ Select ]Question 1 16 pts [ Select ] subtraction Matrices multiplication systems of equations. In solving an equation involving matrices v division in matrices is not possible, so the addition [ Select ] needs to be used. To check to see that the correct inverse has been created, the inverse should be [ Select ] with the original matrix and the result should be the [ Select ]Question 1 16 pts Matrices are extremely useful in solving systems of equations. In solving an equation involving matrices, division in matrices is not possible, so the [ Select ] needs to be used. determinant mutliplicative inverse Gaussian cross product t inverse has been created, the inverse should be [ Select ] v with the original matrix and the result should be the [ Select ]Question 1 16 pts Matrices are extremely useful in solving systems of equations. In solving an equation involving matrices, division in matrices is not possible, so the [ Select ] v needs to be used. To check to see that the correct inverse has been created, the inverse should be v [ Select ] with the original matrix and the result should be the multiplied addedQuestion 1 16 pts Matrices are extremely useful in solving systems of equations. In solving an equation involving matrices, division in matrices is not possible, so the [ Select ] v needs to be used. To check to see that the correct inverse has been created, the inverse should be [ Select ] with the original matrix and the result should be the v [ Select ] commutative property answer identity matrix zeroQuestion 2 12 pts When finding an inverse by hand, the original matrix is written in augmented form. The goal is to get the left side to be the identity matrix, which yields the inverse on the right. About halfway through this process of finding Reduced Row Echelon Form, this matrix is achieved where the leading coefficient of each row is either a 0 or a 1. Start with the augmented matrix above and then follow the mathematical instructions below: R2 = R2 - R1 R3 = R3 - 6R1 R3 = R3 - 4R2 a b d e This results in: 0 1 c g h 0 0 1 k m n Which of the following would be the correct solution after these 3 steps have been applied? O N Na 0 0 1 0 1 0 0 -4 O NO O 0 -1 -1 O N -6 0 1Question 3 24 pts A circle passes through {4, -2] , {-3, 51 , and {6, 2} Using the general form of a circle .172 + y2 + D15 + E]: + F = D and the points above, ll in missing numbers to create the system of equations. {4, -2] creates D l + E l {-3, 5] creates D" + E l + 1F =l l {15, 2] creates [1' + El + 1F =l l Solve the system of equations that you created, and write the equation for the circle by lling in the values for D, E, and F. II c. x2+y2+l lx+l ly+l l Question 4 12 pts Avertical parabola goes through [-2. 43}, {3, 4.3}. and {5, -3?]. Use matrices to solve for D. E. and F, given the general form x2 + J22 + Bx + 133: + F = 0 [since it is a vertical parabola there is. not a 3,!2 term). II It: +l |x+' 'y+