Question $12$

If ${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}f(x)dx=\frac{2}{5}{x}^5-\frac{1}{3}{x}^{2}C,$ then determine a formula for $f(x).$

$($A$)\frac{2}{25}{x}^6-\frac{1}{6}{x}^{3}C$

$($B$)2x^4-\frac{2}{3}x$

$($C$)\frac{8}{5}{x}^4-\frac{1}{3}xC$

$($D$)\frac{1}{15}{x}^6-\frac{1}{9}{x}^{3}C$

$($E$)\frac{1}{15}{x}^6-\frac{1}{9}{x}^3$

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