Question $1$

$2$ pts

A $0\mathrm{.}357$ kg mass is attached to a spring and undergoes a simple harmonic motion. The position of the mass at any time $t$ is given by: $x(t)=0\mathrm{.}602cos(11\mathrm{.}5t),$ where $x$ is in meter and $t$ in second. Where is the mass $($position in meters$)$ at the time $5\mathrm{.}45$ second?

Hint: either set your calculator on radian or convert the phase into degrees.