Question $13(1$ point$)$

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Given the function $f(x)=\frac{5x}{1-3x},$ which of the following is the correct algorithm to find the inverse, $f^{-1}(x)?$

$y=\frac{5x}{1-3x}$

$x=\frac{5y}{1-3y}$

$y=\frac{x}{3x5}$

$f^{-1}(x)=\frac{x}{3x5}$

$x=\frac{5y}{1-3y}$

$y=\frac{5x}{1-3x}$

$y=\frac{x}{3x5}$

$f^{-1}(x)=\frac{x}{3x5}$

$y=\frac{5x}{1-3x}$

$y=\frac{x}{3x5}$

$x=\frac{5y}{1-3y}$

$f^{-1}(x)=\frac{x}{3x5}$

$y=\frac{5x}{1-3x}$

$x=\frac{5y}{1-3y}$

$f^{-1}(x)=\frac{x}{3x15}$

$y=\frac{x}{3x5}$