Question $14(2$ points$)$

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A disk between vertebrae in the spine is subjected to a shearing force of $680$ N $.$ Find its shear deformation taking it to have the shear modulus of $1\mathrm{.}00{10}^9\frac{N}{m^2}.$

The disk is equivalent to a solid cylinder $0\mathrm{.}700$ cm high and $3\mathrm{.}50$ cm in diameter.

Shear deformation, $x=\frac{1}{S}*\frac{F}{A}{L}_0$

$[$Hint: Cross sectional area, A of a cylinder is a circle; Ensure you use SI units$]$

$0\mathrm{.}000000173$ m

$0\mathrm{.}0000962$ m

$0\mathrm{.}00000495$ m

$0\mathrm{.}00000680$ m