Question: Question 1 ( 4 . 5 points ) Consider the polar equation r ( theta ) = 1 + sin ( 3 theta

Question 1(4.5 points) Consider the polar equation r(\theta )=1+sin(3\theta ),(\pi )/(6)=\theta =(5\pi )/(6).
a. Determine the type of symmetry that its graph possesses.
b. Sketch its graph. Use the polar chart below.
c. Set up (do not evaluate) the integral necessary for computing the area bounded by r=1+sin(3\theta ),(\pi )/(6)=\theta =(5\pi )/(6).
Figure 1: A blank polar chart for Question 1.b.
I would appreciate it if you could include an explanation, please.
Question 1 ( 4 . 5 points ) Consider the polar

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