Question $16(1$ point$)$

Find the derivative $of$ the given function.

$g(x)=2co{s}^3(\frac{x}{2})$

$ag(x)=-3co{s}^2(\frac{x}{2})$

$b{g}^{\text{'}}(x)=-3co{s}^2(\frac{x}{2})$

$c{g}^{\text{'}}(x)=-3co{s}^2(\frac{x}{2})$

$d{g}^{\text{'}}(x)=-3co{s}^2(\frac{x}{2})sin(\frac{x}{2})$