Question $17(1$ point$)$

Find the derivative $of$ the given function.

$f(x)=\frac{x^2}{tan(x)}$

$a{f}^{\text{'}}(x)=\frac{2xtan(x)-x^{2}se{c}^2(x)}{ta{n}^2(x)}$

$b{f}^{\text{'}}(x)=\frac{2x}{se{c}^2(x)}$

$c{f}^{\text{'}}(x)=2xse{c}^2(x)$

$d{f}^{\text{'}}(x)=-\frac{2x}{ta{n}^2(x)}$