Question $18$

$1$ pts

An $$ particle $)=(+2e$ moving toward the right at a velocity of vec$(v)=250\frac{(m)}{(s)}$ passes into an electric field with vec$(E)=1000\frac{N}{C}$ pointed in an upward direction. What is the magnitude and direction of the force that the $$ particle experiences as it passes through the electric field?

$||vec(F)||=1\mathrm{.}6*{10}^{-16}N,$ downward

$||vec(F)||=3\mathrm{.}204*{10}^{-16}N,$ upuard

$||vec(F)||=8\mathrm{.}01*{10}^{-14}N,$ upward

$||vec(F)||=2\mathrm{.}27*{10}^{-16}N,$ downward