Question: Question 1: A circle passes through (-2, 6) , (2, 8) , and (5, -1) Using the general form of a circle x~ + y'

 Question 1: A circle passes through (-2, 6) , (2, 8), and (5, -1) Using the general form of a circle x~+ y' + Dx + Ey + F = 0 and the

Question 1:

points above, fill in missing numbers to create the system of equations.(-2, 6) creates D + E + 1F = (2, 8) createsD + E + 1F = (5, -1) creates D + E+ 1F = Solve the system of equations that you created, and

A circle passes through (-2, 6) , (2, 8) , and (5, -1) Using the general form of a circle x~ + y' + Dx + Ey + F = 0 and the points above, fill in missing numbers to create the system of equations. (-2, 6) creates D + E + 1F = (2, 8) creates D + E + 1F = (5, -1) creates D + E + 1F = Solve the system of equations that you created, and write the equation for the circle by filling in the values for D, E, and F. + x+ = 0Avertical parabola goes through [-3. 5}. {4, 33}. and [5. 53]. Use matrices te solve for D. E. and F. given the general form x2 + y2 + D]: + E): + F = [1 [since it is a vertical parabola there is not a y2 term}. x2+' 'x+' 'y+' =0 An ellipse or hyperbola uses the general form Ax- + Cy + Dx + Ey + F =0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficients is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x 2 + Cy + Dx + Ey + F=0 Given 4 points on a vertical ellipse (-1, -5.473), (0, 0.918), (1, 1.107), and (2.753, 0). Select the missing coefficients (answers have been rounded to the nearest tenth). + [ Select ] + [ Select ] v X+ [ Select ] V+ [ Select ] V = 0In the process of finding the inverse of the following matrix, explain the indicated row operation. 2 1 -4 1 0 0 1 2 -3 0 1 0 3 5 -70 0 Step 1: Switch row 1 and row 2. 2 -30 1 0 Answer to Step 1: |2 1 -4 1 0 0 3 5 -70 0 Step 2: Explain the row operation to change the answer from Step 1 to the result below. 2 -3 0 O Answer to Step 2: 0 2 1 0 3 5 -70 0

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