Question: Question (1) a) Give the tightest possible upper bound for the worst case running time for each operation listed a) f(N) = 100 log N2

Question (1) a) Give the tightest possible upper bound for the worst case running time for each operation listed a) f(N) = 100 log N2 + 10 N log N b) f(N) = f(N-1)+N c) f(N) = N2*(2log N + log N)+ N3 d) f(N) = N logN+N log log N e) f(N) = 2 f(N/4) + N2 f) f(N) = N1/4 + log N g) f(N) = 3 f(N/4) +VN h) f(N) = log:(NS)
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