Question: Question 1: Assume that a procedure yields a binomial distribution with n = 1283 trials and the probability of success for one trial isp =

Question 1:

Question 1: Assume that a procedure yields a binomial distribution with n= 1283 trials and the probability of success for one trial isp

Assume that a procedure yields a binomial distribution with n = 1283 trials and the probability of success for one trial isp = 61 % . Find the mean for this binomial distribution. (Round answer to one decimal place.) Find the standard deviation for this distribution. (Round answer to two decimal places.) Use the range rule of thumb to find the minimum usual value \"-20 and the maximum usual value \"+20. Enter answer as an interval using square-brackets only with whole numbers. You really struggle remembering to bring your lunch to work. Each day seems to be independent as to whether you remember to bring your lunch or not. The chance that you forget your lunch each day is 20%. Consider the next 40 days. Let X be the number of days that you forget your lunch out of the 40 days. Calculate the following: (a) \"x: C] 0.; C] (b) What would be the first number of days, larger than the mean, that would be considered unusual (an "outliel")? (Enter a whole number.) [3 (c) Find the probability of forgetting your lunch at least as many times as your answer to part (b). [j

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!