Question: Question 1 Consider the double integral 2/3 1/3 // sin(y3)dA=/ / sin(y3)dydsc. D 0 331/2 (a) Sketch the region D described by the above integral.

$Question 1 Consider the double integral \"2/3 1/3 // sin(y3)dA=/ /$

Question 1 Consider the double integral \"2/3 1/3 // sin(y3)dA=/ / sin(y3)dydsc. D 0 331/2 (a) Sketch the region D described by the above integral. (b) Change the order of integration and calculate the above integral

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