Question $1$

Find the integral.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(\frac{6}{x}-4e^{-0\mathrm{.}5x})dx$

$,-\frac{6}{x^2}+2e^{-0\mathrm{.}5x}+C$

$,6ln|x|-8e^{-0\mathrm{.}5x}+C$

$,6ln|x|+8e^{-0\mathrm{.}5x}+C$

$\frac{12}{x^2}-2e^{-0\mathrm{.}5x}+C$