Question: question 1 Graph the parabola. y=x210x+28 Plot ve points on the parabola: the vertex, two points to the left of the vertex, and two points

question 1

Graph the parabola. y=x210x+28 Plot ve points on the parabola: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graphafunction bqun. Graph the parabola. y=x2+10x21 Plot ve points on the parabola: the vertex, two points to the left of the vertex, and two points to me right of the vertex. Then click on the graphafunction button. 2 Find the xintercept(s) and the coordinates of the vertex for the parabolay=x +10x+25. If there is more than one xintercept, separate them with commas. xinterce pt(s): III vertex: ( Consider the following quadratic function. ffx) = 3x?' 12x5 (a) write the equation in the fonnffx) = a (xh)2+k. Then give the vertex of its graph. Writing in the form specied: f(x) = Vertex: (D, [D (b) Graph the function. To do this, plot five points on the graph of the function: the vertex, two points to the left of the vertex, and two points to the right of the vertex. Then click on the graphafunction button

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