Question: Question 1 ( i ) A power electronics converter is required for a smartphone charger application to charge the battery from the rectified AC mains

Question 1
(i) A power electronics converter is required for a smartphone charger application to charge the battery from the rectified AC mains supply. The charger must supply an output of power of 15 W at 5 V .
- What type of converter could be used for this application?
- Give reasons for your choice with reference to the main design [15\%] considerations for this application.
(ii) A diode data sheet specifies that for a rate of fall of diode current, \( d i / d t=200\mathrm{~A}/\mu \mathrm{s}\), the associated reverse recovery time is 40 ns with \( t_{a}=30\mathrm{~ns}\).
- Briefly explain what is meant by diode reverse recovery and why it may be a problem in a power electronics converter.
- Calculate the expected value of peak reverse recovery current for the conditions given.
- If the diode is used in a Buck converter with an input voltage of 24 V , an output voltage of 5 V , and a switching frequency of 200 kHz , calculate the losses in the diode due to the reverse recovery current.
(iii) A Boost converter delivers an output of 12 V and 2 A from an input voltage of 5 V with an efficiency of \(90\%\). The converter operates in continuous conduction mode at a switching frequency of 500 kHz and requires an inductor of value \(6\mu \mathrm{H}\). The inductor must be designed using one of the ferromagnetic cores from Table 1.
- Choose the best core to use for the inductor and justify your
[25\%] choice.
Table 1.
(iv)- Explain with the aid of a diagram how peak current mode control [20\%] is implemented in a DC-DC converter.
- What advantages does current mode control have compared to [5\%] voltage mode control?
Question 1 ( i ) A power electronics converter is

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