Question $1$

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Given the below circuit: Generator, Step$-$up transformer, transmission line, step down transformer and load

The per$-$phase rating capacity of each device as given by the manufacturer are:

$\backslash$table$[[$Generator:$,40$ MVA,,$22$ KV$,x\%=20\%,,$Y connection with grounded neutral$],[$T$1$:$,30$ MVA,,$\frac{24}{240}KV,x\%=15\%,Y-Y($with grounded neutral$)],[$T$2$:$,20$ MVA,,$\frac{240}{12}KV,,x\%=10\%,Y-Y($with grounded neutral$)]]$

Line: $x=50$ per phase $($actual reactance of the line$)$

Load: $x=10$ per phase $($actual reactance of the load$)$

Using base values of $S_B=80$MVA and base voltage $V_B=16KV($Line to neutral$)$ at the side of generator $($zone$-1).$ Taking into account single phase circuit, find the followings

The base voltage of zone$-1,V_{B1}=$

KV $($No digits after decimal point$)$

The base voltage of zone$-2,V_{B2}=$

KV $($No digits after decimal point$)$

The base voltage of zone$-3,V_{B3}=$

KV $($No digits after decimal point$)$

The base impedance in zone$-1,Z_{B1}=($one digits after decimal point$)$

The base impedance in zone$-2,Z_{B2}=($No digits after decimal point$)$

The base impedance in zone$-3,Z_{B3}=$

$($one digit after decimal point$)$

The new per$-$unit reactance of generator, $x_g=$ pu $($take three digits after decimal point$)$

The new per$-$unit reactance of T$1,x_{T1pu}=$ pu $($one digit after decimal point$)$

The new per$-$unit reactance of T$2,x_{T2pu}=$ pu $($one digit after decimal point$)$

The per$-$unit reactance of transmission line, $x_{\text{T}\text{L}\text{p}\text{u}}=$ pu $($take three digits after decimal point$)$

The per$-$unit reactance of load, $x_{\text{l}\text{o}\text{a}\text{d}\text{.}pu}=$ pu $($one after decimal point$)$