QUESTION $1$

Solve the differential equation.

$x\frac{dy}{dx}=y+(x^2-4{)}^2$

a$.y=x^4-x^2-16+Cx$

b$.y=\frac{1}{3}{x}^4-8x^2-16+Cx$

c$.y=\frac{1}{3}{x}^4-32xlnx+Cx$

d$.y=\frac{1}{3}{x}^3-8x-\frac{16}{x}+C$