Question: Question 1 xcos ( y ) y ^ ( ' ) = 1 + sin ( y ) . ( i ) Find the specific

Question 1xcos(y)y^(')=1+sin(y).
(i) Find the specific solution of this equation that satisfies the initial condition y(1)=0.
(dy)/(dx)=(1)/(x)*(1+siny)/(cosy)=>(cosy)/(1+siny)dy=(1)/(x)dx
=>\int (cosy)/(1+siny)dy=\int (1)/(x)dx=>ln|1+siny|=ln|x|+lnC
=>|1+siny|=C|x|
y(1)=0|->|1+sin0|=C|1|=>C=1
=>|1+siny|=|x|
(ii) The direction field of this differential equation is given below. Sketch the solution
satisfying the initial condition y(1)=0.
i have this question im studying for an exam but im strugling with drawing the directional field if someone could show me in detials and explain the steps i have to take to do it would be highl apreicated
Question 1 xcos ( y ) y ^ ( ' ) = 1 + sin ( y ) .

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