Question: Question 1. Y = -120 x 3 +6000x 2 - 24000x - 480,000 0 ; a. when the advertising cost is $400,000 (x = 40),

Question 1. Y = -120 x3 +6000x2 - 24000x - 480,000 0Question 1. Y = -120 x3 +6000x2 - 24000x - 480,000 0 ;

a. when the advertising cost is $400,000 (x = 40), the profit is _____?

b. We want to see whether we can obtain the profit indicated in the question above using a lower advertising budget. What is the polynomial whose zeros can be an advertising budget lower than $400,000, if we want to obtain the same profit in question 1?

c. The quotient and remainder obtained when the polynomial in the above question is divided by the polynomial ( 40) is _____?

d. Setting the quotient obtained in the above question to 0 and solving for x, we get the lower advertising budget that gives the same profit as _____?

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