Question: Question 1. Y = -120 x 3 +6000x 2 - 24000x - 480,000 0 ; a. when the advertising cost is $400,000 (x = 40),
Question 1. Y = -120 x3 +6000x2 - 24000x - 480,000 0
;
a. when the advertising cost is $400,000 (x = 40), the profit is _____?
b. We want to see whether we can obtain the profit indicated in the question above using a lower advertising budget. What is the polynomial whose zeros can be an advertising budget lower than $400,000, if we want to obtain the same profit in question 1?
c. The quotient and remainder obtained when the polynomial in the above question is divided by the polynomial ( 40) is _____?
d. Setting the quotient obtained in the above question to 0 and solving for x, we get the lower advertising budget that gives the same profit as _____?
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