As a user of the ADT List, consider the method in Between, that receives a list...

 

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As a user of the ADT List, consider the method in Between, that receives a list 1 and two elements el and e2 and returns the number of elements between el and e2. Assume that both el and e2 exist in the list 1, e1 appears before e2 and there are no duplicates. Complete the code below by choosing the correct answer: 1. public int inBetween (List I, Te1, Te2) { Line 3: 2. int count = 0; 3. 4. while (...) { 5. 6. } 7. 8. while (...) { 9. 10. 11. J 12. return count; 13. } 1.findFirst(); if (!1.empty()) 1. findNext(); if (!1. full()) None Activate Windows Go to Settings to activate Windo QUESTION 11 As a user of the ADT List, consider the method inBetween, that receives a list 1 and two elements el and e2 and returns the number of elements between el and e2. Assume that both el and e2 exist in the list 1, el appears before e2 and there are no duplicates. Complete the code below by choosing the correct answer: 1. public int inBetween (List I, Te1, Te2) { Line 4: 2. int count = 0; 3. ... 4. while (...) { 5. 6. } 7. 8. while (...) { 9. 10. 11. } 12. 13.) return count; O O O O O о о !1.retrieve().equals (el) && !1.retrieve().equals (e2) !1. retrieve ().equals (el) || !1.retrieve ().equals (e2) !1.retrieve().equals (el) !1. retrieve ().equals (e2) None QUESTION 5 If we execute the following code on list L with elements: 5, 3, 1, 4, 6 L.findFirst(); while (!L.last()) { L.remove(); L. findNext(); } Then the elements of L will be: 5,1,6 3,4 L will be empty O 3,4,6 QUESTION 6 As a user of an ADT List, and with a list L, the result of calling the method "remove()": Removes the current element and sets the new current to be the first element if no successor of the deleted element exists. All of the above. Removes the current element and sets the new current to the existing successor of the deleted element. Removes the current element and sets it to be NULL if the resulting list is empty. QUESTION 7 As a user of List ADT, the result of calling the method "last()" Return whether the successor of Current is on the last element or not. Return the data of the last element. None Move Current to be on the last element. QUESTION 8 What will this method do to List L? public static <T> void f (List<T> 1) { if (1.empty()) { 1.findFirst(); int cpt 1; while (!1.last()) { } 1.insert(1.retrieve () ); cpt++; 1. findNext(); 1.insert(1.retrieve () ); 1.findFirst(); for (int i = 0; i < cpt; i++) { } 1.remove(); if (!1.last()) 1. findNext(); Duplicates all elements of L. None of the above. Infinite loop. Creates duplicates of all elements of L except the last one. As a user of the ADT List, consider the method in Between, that receives a list 1 and two elements el and e2 and returns the number of elements between el and e2. Assume that both el and e2 exist in the list 1, e1 appears before e2 and there are no duplicates. Complete the code below by choosing the correct answer: 1. public int inBetween (List I, Te1, Te2) { Line 3: 2. int count = 0; 3. 4. while (...) { 5. 6. } 7. 8. while (...) { 9. 10. 11. J 12. return count; 13. } 1.findFirst(); if (!1.empty()) 1. findNext(); if (!1. full()) None Activate Windows Go to Settings to activate Windo QUESTION 11 As a user of the ADT List, consider the method inBetween, that receives a list 1 and two elements el and e2 and returns the number of elements between el and e2. Assume that both el and e2 exist in the list 1, el appears before e2 and there are no duplicates. Complete the code below by choosing the correct answer: 1. public int inBetween (List I, Te1, Te2) { Line 4: 2. int count = 0; 3. ... 4. while (...) { 5. 6. } 7. 8. while (...) { 9. 10. 11. } 12. 13.) return count; O O O O O о о !1.retrieve().equals (el) && !1.retrieve().equals (e2) !1. retrieve ().equals (el) || !1.retrieve ().equals (e2) !1.retrieve().equals (el) !1. retrieve ().equals (e2) None QUESTION 5 If we execute the following code on list L with elements: 5, 3, 1, 4, 6 L.findFirst(); while (!L.last()) { L.remove(); L. findNext(); } Then the elements of L will be: 5,1,6 3,4 L will be empty O 3,4,6 QUESTION 6 As a user of an ADT List, and with a list L, the result of calling the method "remove()": Removes the current element and sets the new current to be the first element if no successor of the deleted element exists. All of the above. Removes the current element and sets the new current to the existing successor of the deleted element. Removes the current element and sets it to be NULL if the resulting list is empty. QUESTION 7 As a user of List ADT, the result of calling the method "last()" Return whether the successor of Current is on the last element or not. Return the data of the last element. None Move Current to be on the last element. QUESTION 8 What will this method do to List L? public static <T> void f (List<T> 1) { if (1.empty()) { 1.findFirst(); int cpt 1; while (!1.last()) { } 1.insert(1.retrieve () ); cpt++; 1. findNext(); 1.insert(1.retrieve () ); 1.findFirst(); for (int i = 0; i < cpt; i++) { } 1.remove(); if (!1.last()) 1. findNext(); Duplicates all elements of L. None of the above. Infinite loop. Creates duplicates of all elements of L except the last one.

Answer rating: 100% (QA)

Line 3 should be completed with java 1 findFirst This initializes the iterator to the beginning of t... View the full answer