Question 11 (1 point) Based on the general rule for finding horizontal asymptotes/the short-cut method developed in class, how would you determine the equation of the horizontal 56332 ., 9322 ' asymptote of the function, f (:12) = The horizontal asymptote equation is found by setting yequal to the quotient of the leading coefficient of the numerator and the leading coefficient of the denominator. O This function has no asymptotes at all because there are no real solutions. 0 The horizontal asymptote equation is found by evaluating the limits. 0 As the degree of the numerator is less than the degree of the denominator, the equation of the horizontal asymptote would be y = 0