Question: Question 14(3 points) Suppose a function z = f ( x , y ) is defined implicitly by the equationx 3 z+2xy 2 2yz 3

 Question 14(3 points) Suppose a functionz=f(x,y) is defined implicitly by the

Question 14(3 points)

Suppose a functionz=f(x,y) is defined implicitly by the equationx

3

z+2xy

2

2yz

3

=1

{"version":"1.1","math":"\(x^3z+2xy^2-2yz^3=1\)"}near the pointp= (3, 2,

{"version":"1.1","math":"-"}1).Then

y

f(3,2)

{"version":"1.1","math":"\(\frac{\partial}{\partial y}f(3,2)\)"}=

Question 14 options:

a)

26

15

{"version":"1.1","math":"\(-\frac{26}{15}\)"}

b)

26

15

{"version":"1.1","math":"\(\frac{26}{15}\)"}

c)

26

19

{"version":"1.1","math":"\(\frac{26}{19}\)"}

d)

15

26

{"version":"1.1","math":"\(-\frac{15}{26}\)"}

e)

26

19

{"version":"1.1","math":"\(-\frac{26}{19}\)"}

f)

15

26

equationx3z+2xy22yz3=1{"version":"1.1","math":"\(x^3z+2xy^2-2yz^3=1\)"}near the pointp= (3, 2,{"version":"1.1","math":"-"}1).Theny f(3,2){"version":"1.1","math":"\(\frac{\partial}{\partial y}f(3,2)\)"}=Question 14 options: a)2615 {"version":"1.1","math":"\(-\frac{26}{15}\)"} b)2615

Question 14 (3 points) Suppose a function z = f (x, y) is defined implicitly by the equation x z + 2xy2 - 2yz = 1 near the point p = (3, 2, -1). Then f (3, 2) = ( a) _ 26 15 ( b) 26 15 O c) 26 19 O d) _ 15 26 O e) _ 26 19 Of) 15 26

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