Question: Question 14(3 points) Suppose a function z = f ( x , y ) is defined implicitly by the equationx 3 z+2xy 2 2yz 3

Question 14(3 points)
Suppose a functionz=f(x,y) is defined implicitly by the equationx
3
z+2xy
2
2yz
3
=1
{"version":"1.1","math":"\(x^3z+2xy^2-2yz^3=1\)"}near the pointp= (3, 2,
{"version":"1.1","math":""}1).Then
y
f(3,2)
{"version":"1.1","math":"\(\frac{\partial}{\partial y}f(3,2)\)"}=
Question 14 options:
a)
26
15
{"version":"1.1","math":"\(-\frac{26}{15}\)"}
b)
26
15
{"version":"1.1","math":"\(\frac{26}{15}\)"}
c)
26
19
{"version":"1.1","math":"\(\frac{26}{19}\)"}
d)
15
26
{"version":"1.1","math":"\(-\frac{15}{26}\)"}
e)
26
19
{"version":"1.1","math":"\(-\frac{26}{19}\)"}
f)
15
26

Question 14 (3 points) Suppose a function z = f (x, y) is defined implicitly by the equation x z + 2xy2 - 2yz = 1 near the point p = (3, 2, -1). Then f (3, 2) = ( a) _ 26 15 ( b) 26 15 O c) 26 19 O d) _ 15 26 O e) _ 26 19 Of) 15 26
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