Question: . Question 17 v Textbook : @' Videos .7 [+] |_9 2000 h A television camera at ground level is 2000 feet away from the

 . Question 17 v Textbook : @' Videos .7 [+] |_92000 h A television camera at ground level is 2000 feet awayfrom the launching pad of a space rocket that is set totake off vertically, as seen in the following figure. The angle ofelevation of the camera can be found by 0:: 6 = 133.111( 2000) where a: is the height of the rocket. Find therate of change of the angle of elevation after launch when thecamera and the rocket are 5990 feet apart. 6' = radians perfoot. Round to five decimal places. 0 Question 16 v > TextbookE @ Videos lf' [+] 225 ft El III E] E] IIIE] [:1 El III DUUUEIEJDEIU DUDDDDDDU EIEICJCIEIEJEIEIU X A building that is225 feet tall casts a shadow of various lengths as the day

goes by. An angle of elevation 19 is formed by lines fromthe top and bottom of the building to the tip of theshadow, as seen in the figure above. d6 Find the rate ofchange of the angle of elevation dWhen a: = 238. :3 6'(238)= ' \\ radians per foot. Round to five decimal places. xQuestion 15 v Next question 5' Get a similar question You IIf at} = 5si11_1(2':5), then f'(m)=i X Question 14 Next question Geta similar qu Let f(x) = tan 1(sin(4x)) f' (a) =. Question13 A Textbook Videos Z [+ If f(x) = 6tan (7 sin(4x)),f' (x) =O Question 12 Textbook Videos = [+] If f(ac) =2 sin -1 (a)), then f' (z) =0 Question 2 v Textbook@ Videos _ [+] dy Use implicit differentiation to determine given the

. Question 17 v Textbook : @' Videos .7 [+] |_9 2000 h A television camera at ground level is 2000 feet away from the launching pad of a space rocket that is set to take off vertically, as seen in the following figure. The angle of elevation of the camera can be found by 0:: 6 = 133.11 1( 2000) where a: is the height of the rocket. Find the rate of change of the angle of elevation after launch when the camera and the rocket are 5990 feet apart. 6' = radians per foot. Round to five decimal places. 0 Question 16 v > Textbook E @ Videos lf' [+] 225 ft El III E] E] III E] [:1 El III DUUUEIEJDEIU DUDDDDDDU EIEICJCIEIEJEIEIU X A building that is 225 feet tall casts a shadow of various lengths as the day goes by. An angle of elevation 19 is formed by lines from the top and bottom of the building to the tip of the shadow, as seen in the figure above. d6 Find the rate of change of the angle of elevation dWhen a: = 238. :3 6'(238) = ' \\ radians per foot. Round to five decimal places. x Question 15 v Next question 5' Get a similar question You I If at} = 5si11_1(2':5), then f'(m)=i X Question 14 Next question Get a similar qu Let f(x) = tan 1(sin(4x)) f' (a) =. Question 13 A Textbook Videos Z [+ If f(x) = 6tan (7 sin(4x)), f' (x) =O Question 12 Textbook Videos = [+] If f(ac) = 2 sin -1 (a)), then f' (z) =0 Question 2 v Textbook @ Videos _ [+] dy Use implicit differentiation to determine given the equation x3 + y = 3. da dy dx Question Help: Video Message instructor Submit Question Jump to Answer.Question4 v | Textbook I: @ Videos I: [+] Find the slope of the tangent line to the curve #323 4mg +y3 = 48 at the point [4, 4). 0 Question 5 v Textbook l: @ Videos J [+] Score on last try: 0 of 10 pts. See Details for r > Next question 3 Get a similar quest Find the slope of the tangent line to the curve 32:2 1mg + 4y3 = 48 at the point [ 2, 2). . Question 7 v

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