Question 19.16Test the null hypothesis at the .01 level of significance that the distribution of bloodtypes for college students complies with the proportions described in the blood bankbulletin, namely, .44 for O, .41 for A, .10 for B, and .05 for AB. Now, however, assumethat the results are available for a random sample of only 60 students. The resultsare as follows: 27 for O, 26 for A, 4 for B, and 3 for AB.

NOTE:The expected frequency for AB, (.05)(60) = 3, is less than 5, the smallestpermissible expected frequency. Create a sufficiently large expected frequency bycombining B and AB blood types.

Table of Observed and Expected Counts

Blood types

O

A

B and AB

Observed count

27

26

7

Expected count

0.44(60) = 26.4

0.41(60) = 24.6

0.15(60) = 9

Answer:

Research problem:5 points

Write down the research problem.

Hypotheses:5 points

Write down the null and alternative hypotheses.

Rejection region / decision rule:5 points

Specify a decision rule.

Test statistic:5 points

Compute chi-square value. Show your work.

Decision:5 points

Make a decision(reject or retain the null hypothesis. Describe why?

Conclusion / interpretation:5 points

Write a conclusion of the hypothesis test in context.