Question $2$

$2$ pts

Simplify the following Boolean functions.

$F(w,x,y,z)=!w!xz+w!xz+!w!x!y!z+!w!xy!z+!wx!y!z+!wxy!z+$

$wxy!z+wx!y!z+w!x!y!z+w!xy!z$

$F(w,x,y,z)=q,$ answer

$*$Please do not include $"F(w,x,y,z)="$ in your solution. Add a single space between variables and operators.