Question $24$

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Consider the function $f(x)=\sqrt[\phantom{2}]{x3}.$

Find the formula for the inverse function.

$f^{-1}(x)=\frac{1}{\sqrt[\phantom{2}]{x3}}$

$f^{-1}(x)=\frac{1}{\sqrt[\phantom{2}]{x-3}}$

$f^{-1}(x)=x^{2}3$

$f^{-1}(x)=x^2-3$